An stone is thrown vertically upwards with the speed of 25km/h and at the same time an another is dropped at 100m high tower. Find the time & distance from ground when they cross each other.
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The first stone when reaches maximum height, it's velocity is zero. Taking initial velocity as 2 m/s and g as negative 10 m/s^2… and using v=u+gt, it works out that it will reach maximum height in 0.2 seconds. Same time it will take to descend from the point of maximum height to ground. Hence its total time of flight in air is 0.4 s. The second stone is thrown 2 s after the first. Hence they will never meet in air. They meet on ground after first stone arrives back that is 0.4 s after it is thrown up …
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