An SUV is traveling at a speed of 18 m/s. If the SUV has a mass of 1,550 kg, what force must be applied to stop it in 8 seconds?
A. –4,030.7 N
B. –2,700.0 N
C. –3,487.5 N
D. –2.25 N
Answers
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Given
u=18m/s
v=0m/s
t=8seconds
m=1550 kg
Solution
a=(v-u)/t
a=(0-18)/8
a=(-18)/8
a=(-9)/4 m/s2
or
a=-2.25 m/s2
From Newton's second law motion
F=ma
F=1550×(-2.25)
F=-3487.5N
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