An SUV is traveling at a speed of 18 m/s. If the SUV has a mass of 1,550 kg, what force must be applied to stop it in 8 seconds? A. -2,700.0 N B. -2.25 N C. -4,030.7 N D. -3,487.5 N
Answers
Answered by
25
Vi = 18 m/s , Vf = 0 m.s , m = 1,550 kg , t = 8 sec
By equation of motion , we get
Vf = Vi + at
0 = 18 + a(8) ⇒ -18 = 8a
8 a = =18
a = -18/8
A = - 9/4
Now
F = ma
F = (1550)( - 9/4)
F = - 3487.5 N
Answered by
36
The answer is -3,487.5 N
I am a Penn Foster student, this is correct.
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