Question

insert 4 Arithmetic mean between 4 and 19

Answer 1

$\huge{Hey Frnd!!!!}$

Here is your answer !

A1=a+d
A2=a+2d
A3=a+3d
A​4=a+4d

Here ,
a= 4
b=19
n=4
d= b-a/n+1= (19-4)/(4+1)= 15/5=3

Hence, d=3
SO substituting in the formulas described at first
A1=a+d=4+3=7
A2=a+2d=4+2(3)=10
A3=a+3d=4+3(3)=13
A4=a+4d=4+4(3)=16

Hope it helps

Answer 2

$hey \: there\pi$
A1=a+d
A2=a+2d
A3=a+3d
A​4=a+4d
Here ,
a= 4
b=19
n=4
d= b-a/n+1= (19-4)/(4+1)= 15/5=3
Hence, d=3
SO substituting in the formulas described at first
A1=a+d=4+3=7
A2=a+2d=4+2(3)=10
A3=a+3d=4+3(3)=13
A4=a+4d=4+4(3)=16........