An tube of 100 Ω, Iron of resistance 50 Ω, and refrigerater of resistance 500
Ω are connected in parallel to a 220 V source. What is the resistance of an
electric iron connected to the same source that takes as much current as all
three appliances, and what is the current through it
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Answer:
Total R=125/4 ohms =31.25
i in 100 ohm tube = 2.2A
I in 50 ohm iron =4.4 A
I in 500 ohm refrejerator= 0.44 ohm
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