Question

An ultrasonic interferometer used to measure the velocity in sea water. If the distance between two consecutive antinodes is 0.55 mm. Compute the velocity of the waves in the sea water. The frequency of the crystal is 1.5 MHz. *

1750 m/sec

1650 m/sec

1450 m/sec

1540 m/sec​

Answer 1

Answer:

1750 m/sec

Mark it brainlist

Answer 2

The velocity of the waves in the sea water is 1650 m/sec.

The velocity of ultrasonic waves in a medium can be calculated using the following formula:

v = fλ

where v is the velocity, f is the frequency, and λ is the wavelength.

Given the frequency of the crystal is 1.5 MHz,

the wavelength can be calculated as follows:

λ = v/f

= $1750 m/sec / 1.5 *10^6 Hz$

=$1.17 x 10^-4 m$

Since the distance between two consecutive antinodes is 0.55 mm, the wavelength can be determined as follows:

λ = 2d

= $2 *0.55 *10^-3 m$

= $1.1 *10^-3 m$

Therefore, the velocity of the waves in the sea water can be calculated as:

v = λf

= $1.1 *10^-3 m *1.5 x*10^6 Hz$

= 1650 m/sec

Thus, the velocity of the waves in the sea water is 1650 m/sec.

To know more about  velocity visit : https://brainly.in/question/11504533

https://brainly.in/question/54346754

#SPJ3