Math, asked by xyakshayxy, 1 year ago

an umbrella is made by stitching 10 triangular pieces of cloth of two different colour each piece measuring 20 CM 50 cm and 50 cm how much cloth of each colour is required for the umbrella

Attachments:

Answers

Answered by Anonymous
157

AnswEr:

Sides of one triangular pieces of cloths are of lengths

  • a = 20 cm
  • b = 50 cm
  • c = 50 cm

Let s be the semi-perimeter of the triangular piece. Then,

 \colon \implies \sf \: 2s = a \:  +  \: b \:  + c \:  \\  \\  \colon \implies \sf \: 2s = 20 + 50 + 50 \\  \\  \colon \implies \sf \: s = 60 \\ \\

 \therefore \:  \triangle \:  =  \sf Area \: of \: one \: triangular \: piece \\  \\  \colon \implies \sf \:  \sqrt{s(s - a)(s - b)(s - c)}  \\  \\  \\  \colon \implies \sf \triangle \:  =  \sqrt{60(60 - 20)(60 - 50)(60 - 50)}  \: cm {}^{2}  \\  \\  \\  \colon \implies \sf \:  \sqrt{6 \times 4 \times 10 \times 10 \times 10 \times 10 }  \:  {cm}^{2}  \\  \\  \\  \colon \implies \sf \: 200 \sqrt{6}   \: {cm}^{2}  \\  \\

\therefore Area of cloth of each colour = 5 × 200 √6 cm²

= 1000 6 cm²

Answered by itzshivam15
19

Answer:

see the attachment

Step-by-step explanation:

hope it helps you

Attachments:
Similar questions