an unbiased cubicle die whose faces are numbered A to F is rolled once. find the probability of getting consonants on the top face
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Total outcomes=6(A,B,C,D,E,F)
Possible outcomes=4(B,C,D,F)
Probability = 4/6=2/3
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Possible outcomes=4(B,C,D,F)
Probability = 4/6=2/3
Hope it helps.
Plz mark brainliest..
Answered by
0
number of favourable outcomes=4
total number of outcomes=6
P(getting a consonant)=number of favourable outcome/total number of outcomes
P(E)=4/6
P(E)=2/3
total number of outcomes=6
P(getting a consonant)=number of favourable outcome/total number of outcomes
P(E)=4/6
P(E)=2/3
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