Question

An under water swimmer sends a sound signal to the surface. It is produces 5 betas/sec when compared with fundamental tone of a pipe of 20 cm length closed at one end what is wavelength of sound in water. (take V water=1500m/secVair=360m/sec)​

Answer 1

Answer:

Let the length of closed pipe is L  1   and that of open pipe is L2

Fundamental frequency of closed pipe, ν  1  =  4L  1

v

where v is the velocity of sound in air.

Frequency of second harmonic of open pipe, ν  2  =  2L  2  v

​Given: ν  1  =ν  2⇒  4L  1v  =  2L  2v⇒  L  2L  1=  21  

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Answer 2

Answer:

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