An unknown gas diffuses 5 times less than that of H2.what is the molecular mass of the unknown gas?
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answer is 50
Explanation:
the rate of diffusion of H2 gas =r2
the rate of diffusion of unknown gas ,r1=5r2
molecular mass of unknown gass =M1
molcular mass of H2 gas=2
rate of diffusion =√molecular mass of unknown gas /Molecular mass of H2 gas
r1/r2=√M1/2
5r2/r2=√M1/2
5/1=√M1/2
squaring on both sides
25/1=M1/2
M1=50
i hope it is helpful!!
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