An unknown gas occupies 322 mL at 29°c and 616 mm . How many molecules are there in this gas?
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Pressure = 0.82atm
Volume = 0.322L
R(constant) = 0.082atm-litre mol(-1) K(-1)
Temperature = 302°
By applying the ideal gas equation
PV = nRT (where n = no.of moles)
(0.82)(0.322) = n(0.082)(302)
Solving the equation....
we get,
n = 0.01
therefore no.of moles = 0.01
So, No.of molecules = (0.01)(Avogadro number)
therefore,
No.of molecules = 6.022 x 10²¹
Hope This Helps...
Volume = 0.322L
R(constant) = 0.082atm-litre mol(-1) K(-1)
Temperature = 302°
By applying the ideal gas equation
PV = nRT (where n = no.of moles)
(0.82)(0.322) = n(0.082)(302)
Solving the equation....
we get,
n = 0.01
therefore no.of moles = 0.01
So, No.of molecules = (0.01)(Avogadro number)
therefore,
No.of molecules = 6.022 x 10²¹
Hope This Helps...
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