Question

an unknown gas of mass 12 grams and molar mass 120 grams is kept in a closed vessel at 1 atm at T degree Celsius. If we increase temperature by 10 degree Celsius, pressure rises by 20%. Find temperature and volume.
Please provide a step-by-step solution.​

Answer 1

Answer:

PV=nRT

PV=nRT=  w/m RT

1×V=   12/12 0  ×R×(273+t)-------(i)

1.1×V=   12/12 0  ×R×(273+t+10)-----------(ii)

Dividing equation (ii) by equation (i), we get

1.1=  (273+t+10) /(273+t)

or t=−173^∘ C

Putting this value in equation (i), we get

1×V=12 /120 ×0.0821×(273−173)

or V=0.821 L

∴V= x×1000=0.821×1000=821

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