Question

- An unstretched spring is 12 cm long. A load
of 5 N stretches it to 15 cm. How long will
it be under a load of 15 N? (Assume that
the spring obeys Hooke's law.)​

Answer 1

Answer:

Explanation:

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Answer 2

Answer:

21cm

Explanation:

F = kx

5 = k(3)

k = 5/3 = 1.67

15 = 1.67(x)

x = 15/1.67

x = 9 cm

Ans = 12 + 9 = 21 cm