Question

An urn B1 contains 2 white and 3
black chips and another urn B2
contains 3 white and 4 black chips,
One urn is selected at random and a
chip is drawn from it. If the chip
drawn is found black, find the
probability that the urn chosen was
B1.
O 417
O 3/7
O 20/41
021/41​

Answer 1

$\large\bf{\underline\green{☕︎Good \: Morning☕︎}}$

refer the attachment ↑

Answer 2

Answer: d)21/41​

Step-by-step explanation:

• We need to find the probability of black  ball from the urn.
• B=prob. of getting black ball, A=ball is from urn B1.
• P(A|B)=P(A∩B)/P(B)
• Hence, P(A|B)=$\frac{\frac{1}{2}*\frac{3}{5} }{\frac{1}{2}*\frac{3}{5}+\frac{1}{2}*\frac{4}{7} }$

                               =$\frac{21}{41}$

• P(A'|B)=1-P(A|B)

                   =$1-\frac{21}{41}$

                   = $\frac{20}{41}$

• Hence, the required answer is option d.

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