Math, asked by akankshajadhav7315, 3 months ago

An urn B1 contains 2 white and 3
black chips and another urn B2
contains 3 white and 4 black chips,
One urn is selected at random and a
chip is drawn from it. If the chip
drawn is found black, find the
probability that the urn chosen was
B1.
O 417
O 3/7
O 20/41
021/41​

Answers

Answered by darksoul3
3

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refer the attachment ↑

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Answered by VaibhavSR
1

Answer: d)21/41​

Step-by-step explanation:

  • We need to find the probability of black  ball from the urn.
  • B=prob. of getting black ball, A=ball is from urn B1.
  • P(A|B)=P(A∩B)/P(B)
  • Hence, P(A|B)=\frac{\frac{1}{2}*\frac{3}{5}  }{\frac{1}{2}*\frac{3}{5}+\frac{1}{2}*\frac{4}{7}  }

                               =\frac{21}{41}

  • P(A'|B)=1-P(A|B)

                   =1-\frac{21}{41}

                   = \frac{20}{41}

  • Hence, the required answer is option d.

#SPJ3

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