Math, asked by cristal, 1 year ago

an urn contain 4 white and 6 red balls .four balls are drawn at random without replacement from the urn .find the probability distribution of number of white ball

Answers

Answered by Anonymous
9
 no. white balls=x
x=0, x=1, x=2,x=3,x=4
P(x=0) = ⁶C₄ /¹⁰C₄
P(x=1) = ⁴C₁  ⁶C₃/¹⁰C₄
P(x=2) =⁴C₂  ⁶C₂/¹⁰C₄
P(x=3) = ⁴C₅ ⁶C₁/¹⁰C₄
P(x=4) = ⁴C₄ / ¹⁰ C₄


cristal: ur ans is wrong
cristal: qus is of cls12
Anonymous: i have corrected
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