an urn contain 4 white and 6 red balls .four balls are drawn at random without replacement from the urn .find the probability distribution of number of white ball
Answers
Answered by
9
no. white balls=x
x=0, x=1, x=2,x=3,x=4
P(x=0) = ⁶C₄ /¹⁰C₄
P(x=1) = ⁴C₁ ⁶C₃/¹⁰C₄
P(x=2) =⁴C₂ ⁶C₂/¹⁰C₄
P(x=3) = ⁴C₅ ⁶C₁/¹⁰C₄
P(x=4) = ⁴C₄ / ¹⁰ C₄
x=0, x=1, x=2,x=3,x=4
P(x=0) = ⁶C₄ /¹⁰C₄
P(x=1) = ⁴C₁ ⁶C₃/¹⁰C₄
P(x=2) =⁴C₂ ⁶C₂/¹⁰C₄
P(x=3) = ⁴C₅ ⁶C₁/¹⁰C₄
P(x=4) = ⁴C₄ / ¹⁰ C₄
cristal:
ur ans is wrong
Similar questions