Question

An urn contains 10 white and 3 black balls. Another urn contains 3 white and 5 black balls. Two are drawn from first urn and put into the second urn and then a ball is drawn from the latter. Find the probablity that it is a white ball.

Answer 1

The probability of white ball will be 13/5 that is 260%

Answer 2

Answer:

Question :

10 white + 3 black balls in first urn

3 white + 5 black balls in second

select 2 balls from first and put into second and find the probao of second urn

Step-by-step explanation:

answer step:

• first chance is select white ball from 1st urn
• second chance select black from 1st urn
• so p(a) = 10/13 ( select white ball )
• so p(b) = 3/13 ( select black ball )

if we select white ball { p(a) } so second urn have 5 white + 5 black

p(w) =

chance of white ball× second urn probability

10/13 × 5/10

50/130

if we select 2 black ball so second urn have

3 white + 7 black

p(b)= chance of black× second urn probability

= 3/13 × 3/10

= 9/130

plus of p(w) and p(b) = 59/130

this is a easiest way of solution..

so pleae like ans..