An urn contains 4 white, 6 black and 8 red balls. if 3 balls are drawn one by one without replacement, find the probability of getting all white balls.
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ans is 1/10 ..........
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Answer:
641/1224 = 0.52369
Step-by-step explanation:
Since , an urn contains 4 white , 6 black and 8 red balls;
So, the total ball in the urn is 18 balls;
According to the question;
3 balls are random from the urn, we have to find the probability of getting all white ball;
Probability of getting white in first attempt is 4/18.
probability of getting white in second attempt from the remaining 3 white ball will be 3/17.
probability of getting white in third attempt from the remaining 3 white ball will be 2/16.
So, the total probability will be sum of all the probabilities i.e 4/18 + 3/17 + 2/16
= 641/1224
0.52369
Hence , the probability would be 641/1224 = 0.52369
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