An urn contains Rs. 600 in the form of Rs. 1, Rs. 5 and Rs. 10 coins and the number of coins are in the ratio of 5:7:8. Find the total number of coins
contained by the urn.
0 100
O 125
0 120
O 102
O 125
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Let the number of Rs.1 ,50 paise and 25 paise be 3,4,12
The value of one rupee coins=Rs.1×3=3Rs.
The value of 50 paise coins=.50×4=2Rs
The value of 25 paise coins =.25×12=3Rs
Total value =3+2+3=8
If the total value is Rs 8 there are 12 coins of 25 paise
If the total value is 600 then the number of 25 paise coins=
8
600
×12=900
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