Question

Analysis of a compound yields the following percent composition by weight: 65.03% Ag, 15.68% Cr, 19.29% O. What is the simplest formula of this compound?

please please answer​

Answer 1

Given :-

• %Ag = 65.03
• %Cr = 15.68
• %O = 19.29
• Atomic mass of Ag = 108 g
• Atomic mass of Cr = 52 g
• Atomic mass of O = 16 g

Solution :-

➥ Relative no of atoms

• Divide the % composition of the elements with their atomic masses

$\longrightarrow\mathtt{Ag = \dfrac{65.0}{ 108} = 0.6}$

$\longrightarrow\mathtt{Cr = \dfrac{15.68}{ 52} =0.3 }$

$\longrightarrow\mathtt{O = \dfrac{19.29}{ 16} = 1.2}$

➥Simple ratio

• Divide all the values obtained above with the least value (i.e. 0.3 in this case)

$\longrightarrow\mathtt{Ag = \dfrac{0.6}{ 0.3} = 2}$

$\longrightarrow\mathtt{Cr = \dfrac{0.3}{ 0.3} = 1 }$

$\longrightarrow\mathtt{O = \dfrac{1.2}{ 0.3} = 4}$

➽ Empirical formula of the compound = Ag 2 Cr O4

The simplest formula of the compound is Ag 2 Cr O4