analysis shows that nickel oxide consists of nickel ion with 96% ions having d8 configuration and 4% having d7 configuration what is the formula of the oxide
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Ni=3d84s2 (At.no.=28)
∴Ni2+=3d8 and Ni3+=3d7
Hence, 96^ ion of Ni2+ and 4% ions of Ni3+ are present,
Let number of O2− ion present in the crystal =x. Applying electroneutraility rule,
Total positive charge =Total negative charge 96×2 (+ve charge)+4×3(+ve charge)=x×2(-ve charge)
∴96×2+4×3−2x=0⇒x=1.02
So formula of crystal
Ni1.00O1.02 or Ni1.00 or Ni0.98O1.00.
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