Question

Given HCF( 3m, 161) = 23 and LCM (3m, 161) = 1449 then the value of m is​

Answer 1

HCF × LCM = Product of two numbers

23×1449= 3m ×161

(23×1449)/161= 3m

3m=(23×1449)/161

m=(23×1449)/161×3

m=69

Answer 2

Answer:

$\large\boxed{\sf{m=69}}$

Step-by-step explanation:

It's being given that,

• HCF (3m, 161) = 23
• LCM (3m, 161) = 1449

Where,

• HCF = Highest Common Factor
• LCM = Lowest Common Multiple

Now, we have to find the value of m.

But, we know that,

• HCF × LCM = Product of numbers

Here, the numbers are (3m) and 161.

Therefore, we will get,

$= >3m \times 161 = 23 \times 1449 \\ \\ = > m = \frac{23 \times \cancel{1449}}{3 \times \cancel{ 161}} \\ \\ = > m = \frac{23 \times \cancel{9}}{ \cancel{3}} \\ \\ = > m = 23 \times 3 \\ \\ = > m = 69$

Hence, the required value of m = 69