Question

Anand had a certain number of chocolates with him he distributed this chocolates among three friends A B and C. To A, he gave half the total number of chocolates with him and five more. To B, he gave one third of the remaining chocolates with him and four more. To C, he gave one fourth of the remaining chocolates with him and 3 more. Finally he is left with 15 chocolates. Find the initial number of chocolates with Anand​

Answer 1

Step-by-step explanation:

Let total choclates with anand be x

choclates given to A = x/2 +5 = (10+x)/2

remaining choclates = x- (10+x)/2= x-10 / 2

choclates given to b = 1/3 × (x-10/2) +4 = x+14 / 6

remaining choclates = x- 22/ 3

choclates given to c = x +14 / 12

choclates left = x-34/ 4

now as per the question

x-34/ 4 = 15

therefore x = 94