Question

and aeroplane taking off from a field has a run of 50 metre what is the acceleration and takeoff velocity if it leaves the ground 10 second after the start​

Answer 1

• See first we find acceleration we knoe that s=ut+1/2at^2 but here u=0 as initially it is at rest so s=1/2at^2 so put s=50 and t=10 we get 50=1/2a×(10)^2 so we get a=1m/s^2
• Now to find takeoff velocity(v) we know v=u+at but u=0 so it becomes v=at put a=1 and t=10 we get value of v as v=10m/s

Answer 2

Answer:

Explanation:D=50 M

                     T=10s

                     U=0m/s as it is starting from rest

To find :a) Acceleration

            b)Take off velocity

Soln > we know that S=ut +1/2at^2

        By substituting values

                  50=0x10+1/2a x 10 x 10

                  50=1/2a x 100

                50 x 2 = a x 100

a= 100/100 , acceleration is 1 m/s

b) Take off Velocity

    we know v=u+at

                    v=0+1 x 10

                    v=1 x 10

                       =10m/s