calculate the radii of first three bohr orbit of hydrogen
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Answered by
36
hii
•••here is our answer•••
Atomic number ,z is equal to 1.
Hence the radius of nth orbit rn=0.529n2Arn=0.529n2A
For first three orbits , n values are 1,2and31,2and3
ratio of radii of first three orbit = r1:r2:r3=n21:n22:n23r1:r2:r3=n12:n22:n32
=> 12:22:3212:22:32
=> 1:4:91:4:9
Answer : 1:4:9
✌✌ hope you like my answer and it may help you ❤❤☺
•••here is our answer•••
Atomic number ,z is equal to 1.
Hence the radius of nth orbit rn=0.529n2Arn=0.529n2A
For first three orbits , n values are 1,2and31,2and3
ratio of radii of first three orbit = r1:r2:r3=n21:n22:n23r1:r2:r3=n12:n22:n32
=> 12:22:3212:22:32
=> 1:4:91:4:9
Answer : 1:4:9
✌✌ hope you like my answer and it may help you ❤❤☺
roshanlepcha64pe3wpu:
using the bohr velocity calculate the radii of an electron in each of the three orbit of hydrogen
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Answered by
21
we know that radius of any orbit of hydrogen atom is given by = 52.9 pm × n²
where n is the respective orbit.
radius of 1st orbit is 52.9 pm × 1² = 52.9 pm
radius of 2nd orbit is 52.9 pm × 2² = 52.9 × 4 = 211.6 pm
radius of 3rd orbit is 52.9 pm × 3² = 52.9 × 9 = 476.1 pm
where pm stands for picometre = 10⁻¹² m
oky i will see
i calculated the radii not the ratio. .
bt my answer is in another way
units must be different in your answer. .type your answers in the comment section
it is 9×10 to the power 9metersquare/columb
how can radius have units meter square/coulomb. . .radius units are either in metres or in centimetres. . .i think you are looking at another answer. .please check again.
hydrogen is equal to 6.63×10to the power-34
it is the value of planks constant that is h = 6.63 * 10 power -34. . . .planks constant is represented by small letter h. .it does not stand for hydrogen.
ok
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