Question

And arrow 2.5 cm height is placed at a distance of 25cm from a diverging mirror of focal length 20 cm find the nature position and size ​

Answer 1

Answer:

here is your answer

u = - 25cm

f = -20cm( concave mirror)

Now from mirror formula

-1/25- 1/v = -1/20

now 1/v = 1/20 - 1/25 = 1/100

v = 100cm

m = -v/u = height of image/ height of object

-100/25 = height of image/ height of object

-100/25 = height of image/ 2.5 cm

Height of image = 4*-2.5 = -10cm

image is real , inverted and 10cm in size