Question

solve x³- x²
it's urgent pls​

Answer 1

Step-by-step explanation:

Given:x³-x²

To find: Factorise the polynomial and find zeros.

Solution:

Step 1: Take x² common from polynomial

${x}^{2} (x - 1)$

Thus, factors of polynomial are x.x.(x-1)

Step 2: Find zeros by putting factors equal to 0

${x}^{2} (x - 1) = 0 \\ \\ {x}^{2} = 0 \\ \\ x = 0 \\ \\ or \\ \\ x - 1 = 0 \\ \\ x = 1$

Thus, zeros of polynomial are 0 and 1.

Final answer:

• Factors are x²(x-1)
• Zeros are 0,1

Remark*: There are multiple zeros at 0. Since it is a cubic polynomial,it must have zero zeros.

Hope it helps you.

To learn more on brainly:

1) if one of the Zeroes of quadratic polynomial (k-1) x²+kx+1 is "-3" then the value of 'k' is...

https://brainly.in/question/42392544

2) If x+ 2a is a factor of a5 -4a²x³ + 2x+ 2a +3, find the value of a.

https://brainly.in/question/42531612

Answer 2

Answer:

solve x³- x² is the question, i think