and engine can pull 500 metric ton load up an inclined plane rising 1 in 10 with speed of 10 M per second the frictional force offered by the plane is 2000 what is the power of the engine
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Answered by
47
HEY DEAR ...
Net upward force in pulling the engine up (f) = mg sinθ + frictional force
where m is the mass of the body = 500×100 = 50000 kg
g is the acceleration due to gravity.
sinθ = 1/100
frictional force = 2000 N
On substituting the value , we get
f = 51000 N
power = force . distance/ time = force . velocity
power = 51000 . 10
= 510000 watt
= 5.1 ×105 watt
HOPE , IT HELPS ...
Net upward force in pulling the engine up (f) = mg sinθ + frictional force
where m is the mass of the body = 500×100 = 50000 kg
g is the acceleration due to gravity.
sinθ = 1/100
frictional force = 2000 N
On substituting the value , we get
f = 51000 N
power = force . distance/ time = force . velocity
power = 51000 . 10
= 510000 watt
= 5.1 ×105 watt
HOPE , IT HELPS ...
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devendra5695:
this i have also made but not getting the answer
ok done
Answered by
28
The answer is 510kW. Hope you understanthe solution.
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