Math, asked by guptamuskan7275, 6 months ago

and
Let C1and C2 be two biased coins such that the probabilities of getting head in a single toss are 2/3 and 1/3
respectively. Suppose alpha is the number of heads that appear when C1 is tossed twice
independently, and suppose beta is the number of heads that appear when C2 is tossed twice,
independently. Then the probability that the roots of the quadratic polynomial x^2-ax+ b we
real and equal, is
(A) 40/81
(B) 20/81
(C) 1/2
(D) 1/4

Answers

Answered by amitnrw
4

Given : C1and C2 be two biased coins such that the probabilities of getting head in a single toss are 2/3 and 1/3  respectively. Suppose alpha is the number of heads that appear when C1 is tossed twice  independently, and suppose beta is the number of heads that appear when C2 is tossed twice,

independently.

To Find: probability that the roots of the quadratic polynomial x²2-αx+ β be

real and equal, is

(A) 40/81

(B) 20/81

(C) 1/2

(D) 1/4

Solution:

alpha is the number of heads that appear when C1 is tossed twice

α     P(α)

0     (1/3)(1/3) = 1/9  

1      (2/3)(1/3) + (1/3)(2/3)  = 4/9

2     (2/3)(2/3)  = 4/9

β is the number of heads that appear when C2 is tossed twice,

β     P(β)

0     (2/3)(2/3) = 4/9  

1      (1/3)(2/3) + (2/3)(1/3)  = 4/9

2     (1/3)(1/3)  = 1/9

x² - αx + β  = 0

Roots are real and Equal if  

α² = 4β

only possible when α & β are zero   or α = 2 & β = 1

α = 0 & β = 0  =>  (1/9 ). (4/9 )   =  4/81

α = 2 & β = 1  =>  (4/9)(4/9 ) = 16/81

4/81 + 16/81

= 20/81

probability that the roots of the quadratic polynomial x^2-ax+ b be

real and equal, is  =  20/81

option B is correct

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