Question

and o
State percentage composition for
each in following
a) C in SrCO3 b) Sin H₂SO4​

Answer 1

Answer:

$\bigstar{\bold{Percentage\:composition\:of\:carbon=8.1\%}}$

$\bigstar{\bold{Percentage\:composition\:of\:sulphur=32\%}}$

Explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

Compounds:

• SrCO₃
• H₂SO₄

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

Percentage composition of:

• C in SrCO₃
• S in H₂SO₄

$\Large{\underline{\underline{\bf{Solution:}}}}$

Percentage composition of Carbon:

→ The molar mass of SrCO₃ is 87.6 + 12 + 48 = 147.6

→ The percentage composition of carbon in SrCO₃ is given by

→ Percentage composition of carbon = (Molar mass of carbon/Molar mass of the compound ) × 100

→ Substituting the datas we get,

  Percentage composition of carbon = (12/147.6) × 100

  Percentage composition of carbon = (0.081 ) × 100

  Percenatage composition of carbon = 8.1 %

$\boxed{\bold{Percentage\:composition\:of\:carbon=8.1\%}}$

Percentage composition of Sulphur:

→ The molar mass of H₂SO₄ is 2 + 32 + 16 × 4 = 98

→ Percentage composition of sulphur = (Molar mass of sulphur/Mass of compound) × 100

→ Substituting the datas we get,

  Percentage composition of sulphur = (32/98) × 100

  Percentage composition of sulphur = 0.32 × 100

  Percentage composition of sulphur = 32 %

$\boxed{\bold{Percentage\:composition\:of\:sulphur=32\%}}$

$\Large{\underline{\underline{\bf{Notes:}}}}$

→ The percentage composition of an element in a compuound is given by,

   Percentage composition of an element = (Molar mass of element/Molar mass of the compound) × 100