Physics, asked by subodhkeshri420, 9 months ago

and object is mating up and incline plane.Its velocity changes from 15m/s to 10m/s in two seconds.What is it's acceleration?​

Answers

Answered by Anonymous
72

\Large{\underline{\underline{\bf{\red{Given}}}}}

  • Initial velocity (u) = 15m/s
  • Final velocity (v) = 10m/s
  • Time taken (t) = 2s

\Large{\underline{\underline{\bf{\red{Find\:out}}}}}

  • Find the acceleration

\Large{\underline{\underline{\bf{\red{Solution}}}}}

Acceleration → The rate of change in velocity by time taken

\large{\boxed{\boxed{\rm{a=\dfrac{v-u}{t}}}}} \\ \\ \\ \implies\rm a=\dfrac{10-15}{2} \\ \\ \\ \implies\rm a=\cancel\dfrac{-5}{2} \\ \\ \\ \implies\rm a=-2.5m/s^2

Hence, the acceleration of object is -2.5m/

Answered by Anonymous
24

\huge\sf\color{navy}{GIVEN:-}

✪ initial velocity = 15 m/s

✪ Final velocity = 10 m/s

✪ Time = 2s

 \huge  \fbox{ \tt \pink{To \: Find:-}}

✪ acceleration ✔✔

\huge\mathtt{FormULa:-}

acceleration (a) \bf\implies  \frac{v-u}{t}

\huge{\bf{\blue{\underline{SOLUTION:-}}}}

acceleration (a) =   \frac{v-u}{t}

\bf\implies  \frac{10-15}{2}

\bf\implies \cancel\frac{-5}{2}

\bf\implies {-2.5m/s^2}

\large\mathtt{Therefore\:The \: acceleration \: is \: object =2.5m/s^2}

\rule{300}{2}

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