Question

and this pls.....................

Answer 1

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Answer 2

$\frac{ sin \: a }{sec \: (90 - a)} + \frac{sin \: (90 - a)}{sec \: a} \\ = \frac{sin \: a}{cosec \: a} + \frac{cos \: a}{sec \: a} \\ = \frac{sin \: a}{ \frac{1}{sin \: a} } + \frac{cos \: a}{ \frac{1}{cos \: a} } \\ = sin \: a \times \frac{sin \: a}{1} + cos \: a \times \frac{cos \: a}{1} \\ = {sin}^{2} a + {cos}^{2} a = 1$
Hence, the value of the trigonometric expression is 1.

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