ane-half the sum of the sides of the mangle
From a group of boys and girls, 15 girls leave. There are then left two boys for each girl
45 boys leave, there are then 5 girls for each boy, The number of girls in the begining was
1) 40
3) 29
Answers
Answered by
3
Answer:
no of girls is 40:- a) 40
Step-by-step explanation:
let no of girls at start be x
when 15 girls leave
no of girls is x-15
there are 2 boys for each girl
no of boys is 2(x-15) = 2x-30
when 45 boys leave
no of boys is 2x-30-45=2x-75
now, there are 5 girls for each boy
hence, no of girls is 5(2x-75) = 10x - 375
but this is equal to x-15 since no of girls has not changed.
=>x-15 =10x-375
9x=360
x=40
no of girls is 40
Answered by
1
Answer:
Algebraically;
B=2(G-15)
5(B-45)=G-15
PIN:
G=29; G-15=14; B=14*2=28; How can 45 boys leave out of 28.
G=40; G-15=25; B=25*2=50; 50-45=5; 5*5=25. Matches the count of girls.
Ans: 1. 40
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