Question

If A is the set of first five natural numbers and B is the set of factors of 12 “

6. If n( A ) = 14; n( B ) = 11; n( A U B ) = 19 then what is the value of n( A⋂B ) ?​

Answer 1

Answer:

The value of n( A⋂B ) would be 6.

Step-by-step explanation:

Since, we know that,

$n(A\cap B) = n(A) + n(B) - n(A\cap B)$

We have,

$n(A\cap B) = 19, n(A) = 14\text{ and } n(B)=11$

By substituting the values,

$19 = 14 + 11- n(A\cap B)$

$19 = 25 - n(A\cap B)$

$19 - 25 = - n(A\cap B)$

$\implies n(A\cap B) = 6$