Anelevator descends into a mine shaft at the rate of 6 m/min. If the descent starts trom lom above the ground level howlong will it take to reach 350 m.
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The distance elevator has to travel = 360 m
rate(6) = distance traveled(360) / time taken(x)
6 = 360 / x
x= 60 minutes
rate(6) = distance traveled(360) / time taken(x)
6 = 360 / x
x= 60 minutes
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