Question

ang 2 3. Given S = 3t + 6t2 (in SI units) then. [ 1 a) the initial velocity is 3 ms'. b) the acceleration is 12 ms 2 c) the displacement of the particle after 2s is 30 m d) the displacement of the particle after 4 s is 30 m ation the change of velocity​

Answer 1

Answer:

5ms−1 at an angle of tan−1 43 with the direction of the initial velocity

Explanation:

After 4 seconds,

vn=0+1×4=4 ms−1 is the velocity perpendicular to the initial.

Hence velocity is given by:

vresultant=(v2normal+v2perpendicular)−−−−−−−−−−−−−−−−−−√=9+16−−−−−√=5ms−1

tanθ=perpendicularnormal=43

Hence, θ=tan−143

Hence option D is correct.