angle 1=108 ° angle 2=36°angle 3 =36° . please give me solution
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As it is a regular pentagon angle sum of property of pentagon is 540
And hence angle 1 = 540\5=108
AE //BD
Hence angle 2 = 36 = angle EBD
BE//DC
so angle BDC = 36
Angle Bed = 108( as it is a regular hexagon)
In triangle BDC
3 + D +C =180
3= 180-36-108
Angle 3 = 36
And hence angle 1 = 540\5=108
AE //BD
Hence angle 2 = 36 = angle EBD
BE//DC
so angle BDC = 36
Angle Bed = 108( as it is a regular hexagon)
In triangle BDC
3 + D +C =180
3= 180-36-108
Angle 3 = 36
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