Question

angle А =48°

angle ACB=18°
what is angle B=?​

Answer 1

Answer:

Step-by-step explanation:

a= 48° and acb=c=18°

the sum of all the angles =180°

a+b+c = 180°

48°+b+18°=180°

66°+b=180°

b=180°-66°

b=114°

Answer 2

Step-by-step explanation:

Given, AB = AC

∠ABC=∠ACB=x (Isosceles triangle property)

In △ABC

∠ABC+∠ACB+∠ABC=180 (Sum of angles of triangle)

x+x+48=180

2x=132

x=66

∘

∠BCA=∠BCD+∠DCB=66

∠BCD=66−18

∠BCD=48

∘

Now, In △BCD

Sum of angles of triangle = 180

∠BCD+∠BDC+∠DBC=180

48+∠BDC+66=180

∠BDC=66

∘

Since, ∠BDC=∠DBC

hence, BD=CD (Isosceles triangle property)

Thus, △BDC is an isosceles triangle.

so

the angle DBC=66