angle ABC=69 degrees,angle ACB=31 degrees find angle BDC
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38
can you please give figure along with this question ......only then we will be able to solve this.....
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7
let angle BCD =x
69+31+x=180. ∆sum property
100+x=180
x=180-100
=80
Hence angle bdc=80°
69+31+x=180. ∆sum property
100+x=180
x=180-100
=80
Hence angle bdc=80°
rupeshkumar2002:
please give figure or more details
no thangs
where did angle BCD camr from?
quesrion is ❌ wrong!!!!!!!!
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