Question

angle ABC and angle DBC are two isosceles triangle on the same base bc and vertices a and d are on the same side of bc .If ad is extended to interest bc at p ,show that angle abd =~ angle acp ,angleabp~=angle acp​

Answer 1

Answer

∠ABC=∠ACB                             (AS ABC IS AN ISOSCELES Δ )

∠DBC=∠DCP                             ( AS DBC IS AN ISOSCELES Δ)

SO  ∠ABC-∠DBC=∠ACB-∠DCB

SO    ∠ABD=∠ACB

Step-by-step explanation:

PLZZ LIKE AND FOLLOW AND GIVE BRAINLEST PLZZZZZZZ