Angle ABD =3 OF ANGLE DAB AND ANGLE BDC=96 . FIND ANGLE ABD.
YOU CAN SEE THE PIC OF THE TRIANGLE IN THE ABOVE PICTURE.
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Answered by
1
Answer:
24°
Step-by-step explanation:
from the fig.,angle BDC=96° therefore angle BDA=180°-96°=84°(linear pair)
angle ABD(let be x)=3angle DAB(3x)
therefore,x+3x+84°=180°
4x+84°=180°
4x=96°
therefore,x=24°
therefore angle ABD=24°
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Answered by
2
Step-by-step explanation:
BDC = 96
BDA= 84 ( LINEAR PAIR )
WE KNOW THAT THE SUM OF ANGLES OF A TRIANGLE IS 180
BDA + ABD + DAB =180
84 + 3 DAB + DAB = 180
84 + 4 DAB = 180
4DAB = 180 - 84
4DAB = 96
DAB = 96÷4
DAB = 24
ABD = 3DAB
ABD = 24× 3
ABD=72
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