Math, asked by impushpa10, 1 year ago

angle ABD and angle ACE is exterior angle of ∆ABC. if angle ABD=110° and angle ACE=150°, then find angle A.​

Answers

Answered by sameersahu25
22
ANSWER
Given
ABD=110
ACE=150
ANGLE ACE +ANGLE ACB=180( Linear pair)
150+ANGLE ACB=180
ANGLE ACB= 30
angle ABD +angle ABC =180( Linear pair)
110+ angle ABC =180
ANGLE ABC = 70
Angle ABC +ANGLE ACB + angle BAC =180 (Angle sum property )
70+ 30+ ANGLE BAC =180
100+ ANGLE BAC =180
ANGLE BAC =80
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Answered by Anonymous
19

Hey Buddy !☺

In figure,

–Angle ABD = 110°

–Angle ACE = 150°

Now,

Angle ABD + Angle ABC= 180°

=> Angle ABC = 180 - 110

=> \fbox{Angle <strong>ABC</strong><strong> </strong>= 70°}

Also,

Angle ACE + Angle ACB = 180°

=> Angle ACE = 180 - 150

=> \fbox{Angle <strong>ACE</strong><strong> </strong>= 30°}

Now,

In ABC,

Angle A + Angle ACB + Angle ABD = 180° Exterior Angle Property】

=> Angle A = 180 - 70 - 30

=> \fbox{Angle <strong>A</strong><strong> </strong>= 80°}

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