angle ABD and angle ACE is exterior angle of ∆ABC. if angle ABD=110° and angle ACE=150°, then find angle A.
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Answered by
22
ANSWER
Given
ABD=110
ACE=150
ANGLE ACE +ANGLE ACB=180( Linear pair)
150+ANGLE ACB=180
ANGLE ACB= 30
angle ABD +angle ABC =180( Linear pair)
110+ angle ABC =180
ANGLE ABC = 70
Angle ABC +ANGLE ACB + angle BAC =180 (Angle sum property )
70+ 30+ ANGLE BAC =180
100+ ANGLE BAC =180
ANGLE BAC =80
MARK AS BRAINLIST ANSWER
Given
ABD=110
ACE=150
ANGLE ACE +ANGLE ACB=180( Linear pair)
150+ANGLE ACB=180
ANGLE ACB= 30
angle ABD +angle ABC =180( Linear pair)
110+ angle ABC =180
ANGLE ABC = 70
Angle ABC +ANGLE ACB + angle BAC =180 (Angle sum property )
70+ 30+ ANGLE BAC =180
100+ ANGLE BAC =180
ANGLE BAC =80
MARK AS BRAINLIST ANSWER
impushpa10:
thank you
Answered by
19
Hey Buddy !☺
In figure,
–Angle ABD = 110°
–Angle ACE = 150°
Now,
Angle ABD + Angle ABC= 180°
=> Angle ABC = 180 - 110
=>
Also,
Angle ACE + Angle ACB = 180°
=> Angle ACE = 180 - 150
=>
Now,
In ∆ ABC,
Angle A + Angle ACB + Angle ABD = 180° 【Exterior Angle Property】
=> Angle A = 180 - 70 - 30
=>
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