Angle b = (3x - 16) what is the supplementary
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hey...
b=3x-16. ...(1)
a=180-(3x-16)
a=180-3x+16
a+b=180
&
a-b=180-3x+16-(3x-16)
a-b=180-3x+16-3x+16
a-b=a+b-6x+32
a=a-6x+32
a=a-2(3x-16)
a=a-2b
0=-2b
b=0
therefore, supplement of 0=180
or
supplement of b =180
b=3x-16. ...(1)
a=180-(3x-16)
a=180-3x+16
a+b=180
&
a-b=180-3x+16-(3x-16)
a-b=180-3x+16-3x+16
a-b=a+b-6x+32
a=a-6x+32
a=a-2(3x-16)
a=a-2b
0=-2b
b=0
therefore, supplement of 0=180
or
supplement of b =180
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