angle B=90 AB=√3 BC prove angle C =60
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In a Triangle ABC,
angle B = 90 , angle C = ?
Given that AB = √3BC
We Know that,
tan C = AB/BC ( tan C = OS / AS )
tan C = √3BC/BC ( AB = √3 BC )
tan C = √3
tan C = tan 60
angle C = 60 ( tan and tan get cancelled )
Hope it helps you.
Thank you
angle B = 90 , angle C = ?
Given that AB = √3BC
We Know that,
tan C = AB/BC ( tan C = OS / AS )
tan C = √3BC/BC ( AB = √3 BC )
tan C = √3
tan C = tan 60
angle C = 60 ( tan and tan get cancelled )
Hope it helps you.
Thank you
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