Angle B is greater than angle C and angle C is greater than angle D show that ad is greater than BC
Answers
Answered by
18
GIVEN
angle b < angle a
angle c < angle d
TO PROVE
AD < BC
PROOF
angle b < angle a
SO,
OA < OB ( SIDE OPPOSITE TO SMALLER ANGLE IS SMALL ITS THEOREM GIVEN IN NCERT) LET THE ABOVE ONE BE 1
NOW,
angle c < angle d
SO,
OD < OC ( SIDE OPPOSITE TO SMALLER ANGLE IS SMALL ITS THEOREM GIVEN IN NCERT)
LET THE ABOVE ONE BE 2
NOW,
ADDING 1 AND 2
OA + OD < OB + OC
ADDING WE GET,
AD < BC
HENCE PROVED
angle b < angle a
angle c < angle d
TO PROVE
AD < BC
PROOF
angle b < angle a
SO,
OA < OB ( SIDE OPPOSITE TO SMALLER ANGLE IS SMALL ITS THEOREM GIVEN IN NCERT) LET THE ABOVE ONE BE 1
NOW,
angle c < angle d
SO,
OD < OC ( SIDE OPPOSITE TO SMALLER ANGLE IS SMALL ITS THEOREM GIVEN IN NCERT)
LET THE ABOVE ONE BE 2
NOW,
ADDING 1 AND 2
OA + OD < OB + OC
ADDING WE GET,
AD < BC
HENCE PROVED
Answered by
1
Step-by-step explanation:
Above answer is correct
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