Question

Angle B of triangle ABC is three - fifth of angle C and angle A is 36 degree. Find the measure of the angle B and angle C. ​

Answer 1

Answer:

Let C be x

A=36

B=3/5x

C=x

Perimeter=Angle(A + B +C)

=>180=36 +3/5x +x

=>180=(180+3x+5x)/5

=>900=180+3x+5x

=>8x=720

=>x=720/8

=>x=90

So,

A=36

B=3/5x=54

C=90

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Answer 2

Answer:

54° and 90°

Step-by-step explanation:

Let angle C is x.

Angle B is three - fifth of angle C.

=> ∠B = (3/5) * x

In a triangle, the three interior angles always add up to 180°:

=> ∠A + ∠B + ∠C = 180°

=>  36 + (3/5) x + x = 180

=> (3/5)x + x = 144

=> 8x = 720

=> x = 90

Then,

<A = 36

<B = (3/5) * 90 = 54

<C = 90

Hence, the measures of <B and <C are 54° and 90°

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