Angle. BCD 25° Angle BAQ 110° ANGLE ACR= 125° FIND x y z
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hope helps you.....
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Hi.
Here but is straight line. So125+25+y=180
Y=30
Angle bac=180straight line. So110+c=180
C=70.
But as we know sum of angles of in a =180,so
In triangle ac.30+70+z=180
Z=80
In triangle ABC a=70b=50sox=
50+70+x=180
X=60
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