Question

factorise :39y3(50y2-98)/26y2(5y+7)

Answer 1

hey here is your answer..

answer is = "3y(5y-7)"

I think my answer is capable to clear your confusion..

Answer 2

Hello , dear friend.
here is Ur solution.._______★

Sol.
$39 {y}^{3} (50 {y}^{2} - 98) \: divide \: \: by \: \: 26 {y}^{2} (5y + 7)$
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$= > 50 {y}^{2} - 98 = 2(25 {y}^{2} - 49)$
=> 2[(5y)²-(7)²]

=> 2[(5y-7)(5y-7)]

$= > \frac{39 {y}^{3}(50 {y}^{2} - 98) }{26 {y}^{2}(5y + 7) } \\ \\ = > \frac{3 \times 13 \times y \times y \times y \times 2 \times (5y - 7) \times (5y + 7)}{2 \times 13 \times y \times y \times (5y + 7)} \\ \\ = > \frac{3 \times y \times (5y - 7)}{1}$
Thus, 39y³(50y²-98) / 26y²(5y+7) = 3y(5y-7)

answer is 3y(5y-7)

Hope it's helps you.
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