angle between two non zero vector A vector and B vector is 120degree then resultant of c vector is
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Here A,B,C are vectors
|A+B|2 = |A|2 + |B|2+ 2A.B (1)
|A-B|2 = |A|2 + |B|2 - 2A.B (2)
on subtracting (2) by (1)
|A+B|2 - |A-B|2 = 4A.B
so C2 = |A-B|2 + 4A.B
or C2 = |A-B|2 +4|A||B|cos120
since cos120 is negative so C will be less than |A-B|
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