If, 1st digit = x
2nd digit = y
3rd digit = z
So, show that a three digit number is divisible by 3 if the sum of its digit is divisible by 3.
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x= 6
y= 3
z= 9
6+3+9= 18
18 is divisible by 3 and 6,3 and 9 is also divisible by 3.
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