Angle DPB=110° , Angle PCB=70°
find arc AYC?
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Answer:
Step-by-step explanation:
ABCD is a cyclic quadrilateral in
which AB = AD
∠BCD = 70°
angle by BD at center = 2 * 70° = 140°
=> m (arc BCD) = 360° - 140° = 220°
m (arc BAD) = 360° - 220° = 140°
∠BCD = 70°
∠BAD + ∠BCD = 180° ( cyclic quadrilateral)
=> ∠BAD + 70° = 180°
=> ∠BAD = 110°
in Δ ADB
AB = AD
=> ∠ADB = ∠ABD
∠BAD + ∠ADB + ∠ABD= 180°
=> 110° + ∠ADB + ∠ADB= 180°
=> 2∠ADB= 70°
=> ∠ADB= 35°
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